Question

Two blocks of masses 10 kg and 3kg are placed along vertical line If the first block is raised through a height of 7cm by what distance should the second Mass be moved to raise the CM by 1cm

Answer 1

Two masses m (1) and m (2) are kept in a vertical line

m (1) = 10 kg, m (2) =3 kg

The first block is raised through a height of 7 cm.

The center of mass raised by 1 cm.

∴1 = $\frac{m_{1}y_{1}+m_{2}y_{2} }{m_{1}+m_{2} }$

    =  $\frac{10*7+3*y_{2}}{40}$

    = $70+3*\frac{y_{2}}{40}$

    → $70+3y_{2}$ = $40$

    → $3y_{2}$ = $-30$

    → $y_{2}$ = $-10$

The 3 kg body should be displaced 10 cm downward in order to raise the center of mass through 1 cm.