Two blocks of masses 10 kg and 5 kg are placed one over the other on a horizontal plane as shown in the figure. If co-efficient of friction is u = 0.2, and an external force F = 45 N is applied horizontally on the lower block, Then, the force of friction in newton) between the two blocks is p=0.2 10 kg
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5kg u=0.2 u=0.2~ 10kg F=25N
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