two blocks of masses 10kg and 20kg are placed on the x-axis. the first mass is moved on the axis by a distance of 2cm. by what distance should the second mass be moved to keep the position of the centre of mass unchanged
Answers
Answered by
3
xcm = m₁x₁+m₂x₂ / m₁+m₂
0 = 10 (2) + 20 (x)/30
20x = -20
x= -1 cm
Which implies the heavier mass is moved 1cm towards left.
praveenmaurya0000:
y did u take cm at origin?
can u tell me what is the accurate ans
Dude first take the positions of 10 kg and 20 kg as x and y.
xcm = 10x+20y /30
k, continue
10kg is moved by 2 cm, so x cm = 10(x+2) + 20y' / 30
since xcm remains same equate RHS
10x + 20y = 10x + 20 + 20y'
y' = y-1
So 20 kg body is moved 1cm towards left
Similar questions