Question

Two blocks of masses 2 kg and 1 kg are in contact with each other on a
horizontal frictionless table. When a horizontal force of 3.0 N is applied to
the block of mass 2 kg, find the value of the force of contact between the two
blocks.​

Answer 1

Answer:

The value of force contact between two blocks is 1N.

Answer 2

Answer:

The value of force contact between two blocks is 1N

Explanation:

The 3.0 N force will cause the total 3 kg to accelerate. The value of that acceleration will be

a = F/m = 3 N / 3kg = 1 m/s^2

Since the 1 kg block is accelerating at 1 m/s^2, the force on it must be

F = m*a = 1 kg*1 m/s^2 = 1 N

Hope it will help you☺