Question

Two blocks of masses 2 kg and 4 kg tied to a string passing over a frictionless pulley. What
will be the magnitude of acceleration of the masses, when they are allowed to move freely?​

Answer 1

Answer:

• acc of system =
• $\frac{net \: force}{mass}$
• $\frac{4 \times 9.8 - 2 \times 9.8}{6}$
• $\frac{19.6}{6}$
• $3.26 \frac{m}{ {s}^{2} }$

Answer 2

Answer:

As the elevator is going upward with acceleration

2

9

so 2log block with focal 2×

2

9

downward & 4log block with focal 4×

2

9

downward as a prudes force.

⇒ weight + pruedo −T=ma

or 4g+2gT=4a ------ (1)

⇒T−(2g+9)=2a i.e. f=ma

or T−3g=2a -------- (2

)

(1)×1 (2)×2 we get 69−T−(2T−69)=+a+a

or 6g−3T+6g=0

T=

3

12g

=4g=40N

Explanation:

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