Question

Two blocks of masses 2 kg are in contact with each other on a
frcitioneiss table. When a horizontal force of 3N is applied to the
block of mass 2 kg. the value o the force of contact between the two blocks is
(A) 4N
B) 3N
(C) 2 N
(D) IN​

Answer 1

Answer:

Considering both blocks as a system,

Total mass of the system M = 3 kg

So, net external force for the system = 3 N (as the table is frictionless)

F = Ma

=> 3 = 3a

=> a = 1 ms

−2

Now considering the block of 1 kg :

a = 1 ms

−2

(acceleration of the 1 kg block is same as the acceleration of the system)

so, F = ma

=> F = 1 kg x 1 ms

−2

= 1 N

HoPe iT HeLpS

Explanation:

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