Question

two blocks of masses 20 kg and 50 kg are placed on the surface of a table on which block you need to apply more pressure to move it and why​

Answer 1

Answer:

two blocks of masses 20 kg and 50 kg are placed on the surface of a table on which block you need to apply more pressure to move it and why

Answer 2

Explanation:

Velocities of  5kg block and 2kg block are 14  m/s and zero respectively.

Let velocity of its centre of mass be VCM

VCM=m1+M2m1v+m2v′

VCM=m1+M2m1v+m2v′VCM=5+25(14)+2(0)=10  m/s

VCM=m1+M2m1v+m2v′VCM=5+25(14)+2(0)=10  m/sVelocity of  5kg block in COM frame,    V=v−VCM=14−10=4  m/s

VCM=m1+M2m1v+m2v′VCM=5+25(14)+2(0)=10  m/sVelocity of  5kg block in COM frame,    V=v−VCM=14−10=4  m/sVelocity of  2kg block in COM frame,    V′=v′−VCM=0−10=−10  m/s

VCM=m1+M2m1v+m2v′VCM=5+25(14)+2(0)=10  m/sVelocity of  5kg block in COM frame,    V=v−VCM=14−10=4  m/sVelocity of  2kg block in COM frame,    V′=v′−VCM=0−10=−10  m/s⟹∣V′∣=10  m/s

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