Question

Two blocks of masses 3m and 2m are in contact on a smooth table. A force P is first applied horizontally on block of mass 3m and then on mass 2m. The contact forces between the blocks in the two cases are in the ratio of

Answer 1

3:2 because forces are divided as3/2

Answer 2

TRICK : here the whole system is moving with constant speed which means that he net force between an of them is 0

Taking the middle part only

Net force = T1 - T2 - 2mg

As the body is moving u , net force on that body provide motion

Therefore T1 - T2 - 2mg = 0

OR

consider the whole block

F - 6 mg = 0 -------- F = 6 mg

consider the first block

F - T1 - mg = m0 = 0 --------------- T1 = 5mg

for the last block

T2 - 3 mg = 0----------------------- T2 = 3mg

For the second block

T1 - T2 - 2mg = 5mg - 3mg - 2mg = 0

                          Hope you understand

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