Two blocks of masses 4 kg and 2 kg are placed side by side on a smooth horizontal surface. A foce of 20 N is applied on 4 kg block. Find (a). The acceleration of each block and (b).the normal reaction between two blocks.
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first block acceleration
F=m*a so a=5 and another a =10 unit m/s2
F=m*a so a=5 and another a =10 unit m/s2
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Total mass of the system is 4+2=6Kg
F=ma
20=6a
a=10/3 m/sec²
(a) both the block move with same acceleration i.e., 10/3 m/sec²
(b) Force exerted by block of mass 2Kg is
F = ma
F = 2*10/3
F = 20/3 N
therefore the normal force is 20/3 N
F=ma
20=6a
a=10/3 m/sec²
(a) both the block move with same acceleration i.e., 10/3 m/sec²
(b) Force exerted by block of mass 2Kg is
F = ma
F = 2*10/3
F = 20/3 N
therefore the normal force is 20/3 N
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