Question

Two blocks of masses 4 kg and 6 kg are placed in contact with each other on a frictionless
surface. A push of 5 N is applied on the heavier mass. What will be the force on the
lighter mass?
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Answer 1

Answer:2N

Explanation:

Here it is

Answer 2

Net acceleration, a = F/(m1 + m2)

a = 5/(4+6) = 0.5 m/s²

This means that both blocks are moving with an acceleration 0.5

So, to find the force on any one of the masses, multiply the mass with acceleration.

Force on 4kg = 4 x 0.5 = 2N