Question

Two blocks of masses 5 kg and 3 kg are placed in contact on
a horizontal frictionless surface as shown in the figure. A
force of 4N is applied on mass 5 kg. The acceleration of the
mass 3 kg will be
4N
>5 kg 3 kg
, m/s2
TTTTTTTTTTTTTTTTTTTTTTTTT7
(c) 2 m/s2
(d) 0.5 m/s2​

Answer 1

Answer:

acceleration of 3 kg block will be 0.5 m/s/s

Explanation:

As we know that the two blocks are connected and placed in contact with each other

So here we will have

$F_{net} = ma$

now we will have

$F_{net}= 4 N$

also the total mass of the two blocks is given as

$m = 5 kg + 3 kg$

$m = 8 kg$

now we have

$4 = 8 a$

$a = 0.5 m/s^2$

#Learn

Topic : Newton's 2nd law

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Answer 2

Explanation:

hope it helps ˙˚ʚ(´◡`)ɞ˚˙