Question

two blocks of masses 6 kg and 4 kg are moving in the same line with the speed 7 metre per second and 2 metre per second respectively they stick together after collision find the common velocity if they are moving 1) in the same direction 2) in opposite direction

Answer 1

Answer:

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Explanation:

Same direction

Initial momentum- 1

M1V1 + M2V2

(7×6) + ( 4× 2)

42 + 8

50 kg m/s

Mid momentum -

Vc = common velocity

M1Vc + M2Vc

(M1 + M2) Vc

10Vc

As we know that

Initial momentum = Mid Momentum

10Vc = 50

Vc = 5 m/s

Different Directions -

Initial momentum -

M1V1 + M2V2

Here, Let V2 be negative because they are in different directions

42 + (-8)

42 -8

= 34 kg m/s

Mid momentum

6 +4 BC

10 Vc

10 Vc = 34 kg m/s

Vc = 3.4 m/s

Answer 2

Answer:

Explanation:

In inelastic collision,we know linear momentum is conserved.As two bodies stick together after collision,it is an inelastic collision.

m1=6kg

u1=7m/s

m2=4kg

u2=2m/s

So,m1u1+m2u2=(m1+m2)v,where v is common velocity.

So,v=((6*7)+(4*2))/(6+4)=5m/s(for same direction)

For opposite direction,m1u1-m2u2=(m1+m2)v

So,v=3.4m/sHope you understood