Question

Two blocks of masses 6kg and 4kg are connected by rope of mass 2kg are resting on a friction less surface.if a constant force of 60N is applied to 6kg block,then the tension in rope at point a,b and c are re spectively given by

Answer 1

a=60/6+4+2=5
Ta=6*5=30n
Tb=5*5=25n
Tc=4*5=20n

Answer 2

A=60/6+4+2=5, Ta=6*5=30n, Tb=5*5=25n, and Tc=4*5=20n.

This means there must be a net force of 10 N on the rope; and this means that the tension on the right of the rope must be 10 N greater than the 6kg block.

Also, the tension could be measured and at point A and B.