Question

Two blocks of masses m and M are kept on a fixed frictionless inclined plane as shown in the figure. The friction coefficient between the surface of the blocks is . The maximum force applied on the block of mass M, along the inclined plane upward, so that both the blocks move together is 12 x N. Find value of x (Take: m = 5kg, M = 10 kg, μ=0.8,0 = 37,9 10 m/s²)​

Answer 1

Answer:

987 kg will be the answer

Explanation:

hope it help you

Answer 2

That the blocks move together is the block A moves down the plane.

Explanation:

The force acting down the plane for blocks A and B are,

$F_{a}=Mgsin60^{0}$

$=\frac{\sqrt{3} }{2}Mg$

$=0.866Mg$

$F_{b}=Mgsin30^{0}$

$=\frac{1}{2}Mg$

$=0.5Mg$

$F_{a}$>$F_{b}$ the block A moves down the plane.