Question

two blocks of masses M1 = 5 kg and M2 = 6 kg are on either sides of the wedge find the acceleration and tension in the rope

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Answer 1

hay mate

M1

Fx=T-m1gsin30= m1a=plug in tension of the rope= 36.5-5kg(9.8)sin30=5a a=2.4

Fy:Fn1-m1gcos30=m1a=0

M2

Fx=m2gsin60-T=plug in tension of the rope=6kg(9.8)sin60-36.5=14.4222937424992=6a=2.4

Fy=Fn2-m2gcos60=0

T-m1gsin30=m1a

-t+M2gsin60=m2a

A=(T-m1gsin30)/m1

Combine eq

-t+M2gsin60=m2((T-m1gsin30)/m1))

-t+6kg(9.8)sin60=6kg((T-5*9.8sin30)/5)

-t+50.9= 6((T-24.5)/5)

-t+50.9 = 6/5t -29.4

80.3=2.2t

T=36.5N

it may be useful to you

have a nice day