Question

Two blocks of same mass are kept on a horizontal rough surface as shown in the figure. Coefficient of
friction between the blocks and surface is 0.1. A force of 16 N is applied on one block as shown in
figure. Find the tension (in newton) in the string.
string
5kg
5kg
16N
u=0.1
(A) 4
(B) 6
(C) 8
(D) 10​

Answer 1

Answer:

asdfghjklpoiuytrewqzxcvbnm

Explanation:

addfggjjko

Answer 2

Explanation:

• So there are two blocks of 5 kg and a force of 16 N.
• So we have m = 5 kg
• So coefficient of friction μ = 0.1
• So from the first block we get
•              So f max = μN
•                              = μmg
•                              = 0.1 x 5 x 10
•                     Or f max = 5 N
• Now we have
•                           T – f = ma
•                            T = f + ma
•                            F – T – f = ma
•                            F – f – ma – f = ma
•                        So F – 2f = 2 ma
•                  Substituting we get
•                               16 – 2 (5) = 2 x 5 x a
•                                16 – 10 = 10 a
•                                    10 a = 6
•                                   Or a = 6/10
•                                  Or a = 0.6 m/s^2
•         Now T = f + ma
•                       = 5 + 5 x 0.6
•                       = 8
•                   Or T = 8 N

Reference link will be

https://brainly.in/question/20103652