Question

Two blocks P and Q of different metals having their mass in the ratio 2:1 are given the same amount of heat. Their temperatures rise by the same amount, compare their specific heat capacities.​

Answer 1

Answer:

1:2

Explanation:

S = Q/M∆t

S1/S2 = (Q/M1∆t)/(Q/M2∆t)

S1/S2 = M2/M1

S1/S2 = 1/2

S1:S2 = 1:2

Answer 2

Answer:

• The required ratio is 1 : 2.

Explanation:

Let Cp and Cq be the specific heat capacities of blocks P and Q respectively.

We know that,

$\purple \bigstar \: \: \boxed{\sf C = \frac{ Q }{ m} × \Delta \: t}$

Now,

$\leadsto \: \sf \: \frac{Cp }{ Cq }= \frac{ ( \frac{Q }{2m }× \Delta t)} { ( \frac{Q} {m }× \Delta t)}$

$\leadsto \: \sf \: \frac{ Cp}{ Cq} = ( \frac{Q }{2m }× \Delta t) × ( </h3><h3>m × \frac{ \Delta t}{Q})$

$\leadsto \: \boxed{\sf \: \frac{Cp} { Cq} = \frac{ 1} {2}} \: \: \red \bigstar$