Question

Two blocks P and Q of masses 4 kg and 3 kg on a smooth surface are acted on by a force of 14 N. Find the acceleration of the blocks and the contact force between the blocks P and Q. *

Answer 1

F

F net

F net

F net =45−9=36N

F net =45−9=36NF

F net =45−9=36NF net

F net =45−9=36NF net

F net =45−9=36NF net =M

F net =45−9=36NF net =M net

F net =45−9=36NF net =M net

F net =45−9=36NF net =M net a

F net =45−9=36NF net =M net a sys

F net =45−9=36NF net =M net a sys

F net =45−9=36NF net =M net a sys

F net =45−9=36NF net =M net a sys F

F net =45−9=36NF net =M net a sys F sys

F net =45−9=36NF net =M net a sys F sys

F net =45−9=36NF net =M net a sys F sys =

F net =45−9=36NF net =M net a sys F sys = 9

F net =45−9=36NF net =M net a sys F sys = 936

F net =45−9=36NF net =M net a sys F sys = 936

F net =45−9=36NF net =M net a sys F sys = 936 =4m/s

F net =45−9=36NF net =M net a sys F sys = 936 =4m/s 2

F net =45−9=36NF net =M net a sys F sys = 936 =4m/s 2

F net =45−9=36NF net =M net a sys F sys = 936 =4m/s 2 N−9=4×a

F net =45−9=36NF net =M net a sys F sys = 936 =4m/s 2 N−9=4×aN=16+9

F net =45−9=36NF net =M net a sys F sys = 936 =4m/s 2 N−9=4×aN=16+9N=25N

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