two blocks whose sum of masses is 1kg were arranged as shown. Acceleration of blocks is twice, when A is hanging that of when B is hanging, the mass of A is (neglect friction)
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Explanation:
two blocks whose sum of masses is 1kg were arranged as shown. Acceleration of blocks is twice, when A is hanging that of when B is hanging, the mass of A is (neglect friction)
Given info : two blocks whose sum of masses is 1 kg were arranged as shown in fig. acceleration of blocks is twice when A is hanging that of when B is hanging.
To find : the mass of A is ..
solution : let the mass of A is m₁ and the mass of B is m₂.
case 1 : when block A is hanging,
m₁g - T = m₁a ...(1)
T = m₂a ...(2)
from equations (1) and (2) we get, a = m₁g/(m₁ + m₂) ...(3)
case 2 : when block B is hanging,
m₂g - T = m₂a' ...(4)
T = m₁a' ...(5)
from equations (4) and (5) we get, a' = m₂g/(m₁ + m₂) ..(6)
a/c to question,
a = 2a'
⇒ m₁ = 2m₂
but the sum of masses = m₁ + m₂ = 1 kg
⇒ m₁ + m₁/2 = 1kg
⇒ m₁ = 2/3 kg
therefore the mass of block A is 2/3 kg.