Two boats approach a light-house from opposite directions. The angle of elevation of
the top of the lighthouse from the boats are 30o
and 45o
. If the distance between these
boats be 100 m, find the height of the lighthouse.
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Answered by
91
Tan30 = H/x
H = x/√3
Tan45 = H/(100 - x)
H = 100 - x
100 - x = x/√3
100√3 - x√3 = x
x = 100√3/(1 + √3)
H = x/√3
H = 100√3/(√3×(1 + √3))
H = 100/(1 + √3)
H = 100/2.732
H = 36.60 m
Height of the lighthouse is 36.60 m
H = x/√3
Tan45 = H/(100 - x)
H = 100 - x
100 - x = x/√3
100√3 - x√3 = x
x = 100√3/(1 + √3)
H = x/√3
H = 100√3/(√3×(1 + √3))
H = 100/(1 + √3)
H = 100/2.732
H = 36.60 m
Height of the lighthouse is 36.60 m
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