Two boats go downstream from point X to point Y. The faster boat covers the distance from X to Y 1.5 times as fast as the slower boat. It is known that for every hour the slower boat lags behind the faster boat by 8 km. However if they go upstream then the faster boat covers the distance from Y to X in half the time as the slower boat. Find the speed of the slower boat in still water?
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Answer:
the speed of the slower boat in still water = 12 km/Hr
Step-by-step explanation:
Let say Speed of Faster Boat = F km/hr
Speed of Slower Boat = X km/Hr
Speed of stream = S km /hr
Speed of Faster Boat during downstream = F + S km/hr
Speed of Slower Boat during downstream = X + S km/hr
F + S = 1.5 ( X + S)
F + S - X + S = 8
=> F = X + 8
X + 8 + S = 1.5 ( X + S)
=> X + 8 + S = 1.5X + 1.5S
=> 0.5 X + 0.5S = 8
=> X + S = 16
Upstream speeds
F -S & X - S
F-S = 2(X -S)
=> F - S = 2X - 2S
=> F + S = 2X
=> X + 8 + S = 2X
=> X - S = 8
Adding both equation
2X = 24
X = 12 km/hr
the speed of the slower boat in still water = 12 km/Hr
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