Two bodies A and B are kept in
an evacuated vessel maintained at a temperature of
27 °C. The temperature of A and B are 527 °C and
127 °C, respectively. Compare the rates of their
heat emission.
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Answer:
From Stefan's Law:
Δt
ΔQ
=σeA(T
4
−T
o
4
)
ΔQ
B
ΔQ
A
=
700
4
−300
4
600
4
−300
4
=0.52
The ratio of rates of loss of heat can be found from the Stefan's equation. T is given as 600K for A and 700K for B, the T
o
is 300K in both the cases, on calculation the ratio of heat loss comes around 0.52.
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