Question

Two bodies A and B have their masses in the ratio 3:1 and kinetic energy in the ratio 1:3. then ratio of their velocities are

Answer 1

Your answer is :-


Let, the mass of body A be 3x and mass at d body B be 1x

°•° ration of their kinetic energy is 1:3

So,


(1/2m1v1^2)/(1/2m2v2^2) = 1/3

=> (3x×v1^2)/(x×v2^2) = 1/3

=> v1^2/v2^2 = 1/9

=> (v1/v2) = √(1/9)

=> v1/v2 = 1/3


hence, ration of their velocity is 1:3

Answer 2

HEY MATE HERE IS YOUR ANSWER

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Given :-

Two bodies A and B have their masses in the ratio 1 :3

Let the ratio be x.

Therefore,

Mass of body A = 3x

And

Mass of body B = 1x

$\huge = > \frac{ \frac{1}{2}m1v {1}^{2} }{ \frac{1}{2} m2v {2}^{2} } = \frac{1}{3}$

$\huge = > \frac{3x \times v {1}^{2} }{x \times v {2}^{2} } = \frac{1}{3}$

$\huge = > \frac{v {1}^{2} }{v {2}^{2} } = \frac{1}{9}$

$\huge = > ( \frac{v1}{v2}) = \sqrt{( \frac{1}{9}) }$

$\huge = > \frac{v1}{v2} = \frac{1}{3}$


Therefore,

Their Ratio of their velocity is 1 : 3

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