Two bodies A and B have their masses in the ratio 3:2 and their potential energies are in the ratio 2:3. What is the ratio of the height to which they are raised?
Answers
Answered by
0
Explanation:
m
2
m
1
=
1
3
and
KE
2
KE
1
=
3
1
2
1
m
2
v
2
2
2
1
m
1
v
2
1
=
3
1
m
2
m
1
λ(
v
2
v
1
)
2
=
3
1
3(
v
2
v
1
)
2
=
3
1
v
2
v
1
=
9
1
=1:3
Answered by
2
Let
- masses are 3m and 2m
- Potential energies=2p,3p
Acceleration due to gravity(g) is constant
We know
From first case
From second case
Ratio
- cancel p,m,g
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