two bodies A and B have velocities in the ratio of 2 ratio 1 mass of body is half of the mass of body be the Kinetic energies of A and B are in the ratio of
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Let the velocity of first body = v
That gives us ,
(1/2)*m*(2v)^2 = (1/2)*m*v^2
4v^2 = v^2
Therefore , the ratio is 4:1
Thanks
That gives us ,
(1/2)*m*(2v)^2 = (1/2)*m*v^2
4v^2 = v^2
Therefore , the ratio is 4:1
Thanks
shubham16179:
it's answer 2:1
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