Question

two bodies A and B of equal mass are kept at height of H and 2H respectively. what will be the ratio of their potential energy.

Answer 1

potential energy is mass*acceleration due to gravity *height
the ratio of the height is 1:2
as the masses are the same the ratio for f the potential energy is 1:2

Answer 2

Hey there!

Mass of first body = Mass of second body

i.e $M_A = M_B$

Heights = h and 2h respectively.

Now,

$\dfrac{P.E_{A}}{P.E_B}\\\\=\dfrac{mgh}{mg2h}\\\\=\dfrac{1}{2}\\\\=1 : 2$

Hope it Helps You!