Question

two bodies A and B of equal masses are kept at height H and 2H 16 what will the ratio of their potential energy

Answer 1

Mass of A = Mass of B = m
height of A = H
height of B = 2H
Potential energy of A = mgH
potential energy of B = mg(2H)= 2mgH
their ratio =
$\frac{mgh}{2mgh} = \frac{1}{2}$
ratio = 1:2

Answer 2

Hey there!

Mass of first body = Mass of second body

i.e $M_A = M_B$

Heights = h and 2h respectively.

Now,

$\dfrac{P.E_{A}}{P.E_B}\\\\=\dfrac{mgh}{mg2h}\\\\=\dfrac{1}{2}\\\\=1 : 2$

Hope it Helps You!