Two bodies a and b of equal masses are kept at heights of H and 2H.what will be the ratio of their potentional energies
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Answered by
0
Answer:
1:2
Explanation:
The ratio of their potential energies are:
mgh/m1g1h1
m=m1
G is constant
Therefore,
H/2H
=1/2
Answered by
1
Explanation:
potential energy = mgh
we need to find the ratio so
mgh/ mgh = as the masses are same so they will cancel out and as a result we will get ratio as 1/2.
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