Question

two bodies a and b of equal masses are kept at heights of h and 2h respectively. what will be the ratio of their ​

Answer 1

Answer:

Mass of body A, m

1

=m

Mass of body B, m

2

=m

Height h

1

=h

Height h

2

=2h

Acceleration due to gravity, g

1

=g

Acceleration due to gravity, g

2

=g

PotentialEnergy(P.E

2

)

PotentialEnergy(P.E

1

)

=?

P.E=mgh

⇒P.Eαh

(∴ 'm' and 'g' are constants)

⇒

P.E

2

P.E

1

=

h

2

h

1

⇒

P.E

2

P.E

1

=

2h

h

⇒

P.E

2

P.E

1

=

2

1

Therefore, the ratio of potential energy is of the two bodies is 1 : 2.