Two bodies A and B of mass 150 g and 250 g respectively are approaching each other. Both particles have a speed of 3 m/s. Find the magnitude of the total linear momentum of the system of two particles.
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Mass of body A, ma = 150 g = 0.15 kg
Mass of body B, mb = 250 g = 0.25 kg
Both the bodies are moving towards each other. Let the direction of B be taken as positive. Then the direction of A will be considered negative.
Velocity of A, va = - 3 m/s
Velocity of B, vb = 3 m/s
Now, total momentum of the system,
P = mava + mbvb
=> P = (0.15)(-3) + (0.25)(3)
=> P = -.45 + .75
=> P = 0.30 Ns
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