Physics, asked by royfalcon002, 1 year ago

two bodies a and b of masses 100g and 200g respectively are dropped near earth's surface let the acceleration of A and B be a1 and a2 respectivly


YourFriend1: are u asking for their acceleration
royfalcon002: more like an mcq
royfalcon002: options are
royfalcon002: a) a1=a2 b) a1<a2 c)a1>a2 d)a1=/=a2
YourFriend1: option a)

Answers

Answered by YourFriend1
45
Are u asking for their acceleration?
If yes then their acceleration will be the same(I.e 9.8m/s^2) because acceleration due to gravity doesn't depend on mass of the object

royfalcon002: more like an mcq

options are

a) a1=a2 b) a1<a2 c)a1>a2 d)a1=/=a2
royfalcon002: btw thankyou (brother or Sister)
YourFriend1: option a)a1=a2 if u found my answer useful mark it as the BRAINLIEST
royfalcon002: option for brainliest not here (brother or sister)
YourFriend1: Brother
royfalcon002: ok
Answered by Pratyay16
24
if the question has asked to find the time when they reach the bottom then it will be same for both A and B .

as we know H = 0t + 1/2 gt^2 or t = (2H/g)^2

● Only the impulse of heavier body will be more .
Their acceleratn has to be Same .

if Suppose they are a1 and a2 . Then it may be due to air friction and also air is different in the places where A and B are dropped.

● Therefore in that case consider net acceleration to be a1 and a2 .

a1 = g - (accln due to air friction in atmosphere1)

a2 = g - (accln due to air friction in atmosphere 2)
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