Question

two bodies a and b of masses 3kg and 2kg are connected by a string as shown in the figure .if the table and pulley are frictionless the common acceleration of the system is (g=10ms-1)​

Answer 1

Answer:

10 m/s

Explanation:

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Answer 2

The velocity(v)= $2m/s^{2}$.

Explanation:

If a is the acceleration of the system, then the equation of motion of the system,

$(m1+m2)a=F_{net}$

$F_{net}=(m1-m2)g$

$a=\frac{m1-m2}{m1+m2}g$

$a=\frac{3-2}{3+2} 10ms^{-1}$

$a=\frac{1}{5}10ms^{-1}$

10 (milliseconds^(-1)) =  10 kilohertz

$a=2$

 Now using , $v=u+at$ where $u=0$ and $t=1 s$

$v=at$

$v=2$ × $1$

$v=2m/s^{2}$

The velocity(v)= $2m/s^{2}$.