Question

Two bodies A and B of masses m and 2m respectively are kept a distance d apart . Where should a small particle be placed so that the net gravitational force done to the bodies A and B is zero

Answer 1

Distance of Third particle from m is

x = d/√2+1

from 2m

x = √2d/√2+1

Answer 2

Answer:

X = √d/2+1

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