Question

Two bodies A and B start from the same point at the
same instant and move along a straight line. A moves
with a uniform acceleration and B moves with a
uniform velocity. They meet after time t. What is
the value of ?​

Answer 1

The answer is 2v/a

where v is the constant velocity of the B and 'a' is the uniform acceleration of the body A.

We apply the equation of motion to the body A

s=ut+1/2at^2

The initial velocity of A is u=0

The aceleration is a =a

So, the distance after the time t is=0+1/2at^2

We apply the equation of motion to the body B

s=vt. as acceleration of B is 0, constant velocity

Therefore,

vt=1/2at^2

t=2v/a