Question

Two bodies, A (of mass 1 kg) and B (of mass 3 ko
are dropped from heights of 16 m and 25 m
respectively. The ratio of the time taken by them to
reach the ground is​

Answer 1

Answer:

So here the mass is given of the two bodies as 1 Kg and 3Kg

• Ratio of time taken by these bodies will be irrespective of their masses because gravity acts similar to all bodies provided in vaccum!
• By second eq of motion i.e. S(displacement) = ut + ½gt²
• Hence it is dropped then the initial velocity is obviously zero
• Then it goes like this -: S = ½gt²
• For the first body i.e. on 16m
• 16 = ½*10*t² ( g = 10m/s²)
• t = 4/√5 sec
• For second body 25m
• 25 = ½*10*t²
• t=√5 sec
• HOPE IT HELPS:)