Two bodies a of mass 1kg and b of mass 3 kg are dropped from height 16 and 25 respectively the ratio of the time taken by them to reach the ground is
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Answer:4:1
Explanation:Let the time be t1 and t2.As their motion does not depend on the mass and the bodies fall with acceleration a=10(assuming downward direction as positive)
u=0
Then for body 1=
As the acceleration is constant
S=ut1 +1/2*a*t1^2
16=0+1/2*10*t1^2
t1^2=16/5
t1=4/✓5
Similarly for t2
S=ut2+1/2*a*t2^2
25=0+1/2*10*t2^2
t2^2=5
t2=✓5
t1/t2=(4/✓5)/✓5=4/5=4:5
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