Question

two bodies Aand B of unequal masses same momentum have masses in the ratio 1:2 then their K.E are in the ratio

Answer 1

k.e. will be in the ratio of 1:4

K.E = 1/2mv*mv  

mass1 = m  

mass2 = 21  

Then, K.E of mass1 = 1/2mv*mv

and K.E of mass2= 1/2*2mv*2mv  

Then divide K.E of mass1 and mass2

So,(1/2mv*mv)/(1/2*2mv*2mv)

We get, 1/4

Then ratio = 1:4