Two bodies are in equilibrium when suspended in
water from the arm of a balance. The mass of one
body is 60 g and its density is 12 g cm. If the mass
of the other body is 72 g, its density in g cmis
A. 6.25
B. 6.75
C. 2.33
D. 4.23
Answers
Answered by
5
Answer:
D. 4.23 g cms
Explanation:
Let the mass of 1st body be 'A' and the 2nd 'B'.
Now...
Mass 'A' - mass 'A'/density 'A' = Mass 'B'-mass 'B'/ density 'B'. ....1)
Let the density of 'B'be 'x'
Therefore,
60-60/12=55.
72-72/x=55........... (from 1)
72-55=72/x
17=72/x
x=4.23
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