Two bodies are moving wahame kinetic energy and their masses are in the ratio 1:2. Then of
a)1:1
b)1:2
c)root 2:1
d)2:1
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Answer:
K.E. = mv^2/2 = (mv)^2/2m = p^2/2m.
If mass and momentum of first are m & p, and of second are M & P then
p^2/2m = P^2/2M thus p^2/P^2 = 2m/2M
or p/P = sqrt(m/M) = sqrt(2/4) = sqrt(1/2
Explanation:
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