Question

two bodies are projected simultaneously with the same velocity of 19.6 metre per second from the top of Tower one vertically upwards and other vertically downwards as they reach the ground the time gap is​

Answer 1

Answer:

Time Gap = 4 sec

Explanation:

two bodies are projected simultaneously with the same velocity of 19.6 metre per second from the top of Tower one vertically upwards and other vertically downwards as they reach the ground the time gap is​

Velocity = 19.6 m/s

One is thrown vertically upward & other is thrown downward

Time gap in both to reach ground will be equal to time taken to go highest point and then come back to throwing point . Let say T

then time to reach highest point = T/2

at highest point Velocity  = 0

Using V = u + at

U = 19.6 m/s

a = -g = -9.8 m/s²

t = T/2

V = 0

0 = 19.6 - 9.8(T/2)

=> T = 4

Time Gap = 4 sec

Answer 2

Answer:

4 seconds

Explanation:

I hope you have the correct answer