Question

two bodies are projected vertically upwards with a velocity of 49m/s. They are projected with the time gap of 2 sec.
After the projection of first body, they will meet in a time of ?

Answer 1

Answer:

6 seconds

Explanation:

When they meet, their displacements will be same. Therefore ,

s= ut-(1/2)gt^2=u(t-2) -(1/2)g(t-2)^2

Simplifying and making t subject, we get

t=(u+2g)/2g. OR

Substituting the values,

t=(98+19.6)/19.6 OR

t=6s after the first body was thrown.

hope it helps