Question

two bodies are projected with velocity u1 and u2 at angle theata1 and theata2 with respect to horizontal. what will be the nature of path of body A with respect to B? ​​

Answer 1

Answer:

$\mathbb{\huge{\underline{\underline{\red{ANSWER}}}}}$

Both particles collide at the highest point.It means the vertical distance travelled by both particle will be equal,.i.e., the vertical component of velocity of both particles will be equal u1 sin30°...

= u2

$\mathrm\frac{u1}{2}$

= u2----> u1 = 2u2.

Answer 2

Explanation:

Let both bodies collide after t sec.

displacement in vertical direction by 1st particle = displacement in y direction by 2nd particle

1st particle is projected with speed u_1 at an angle 60° with horizontal.

after time t sec vertical displacement,

$S = u_1sin60^{\circ}t-\frac{1}{2}gt^2$

displacement of 2nd particle after time t sec.

$S = u_2t-\frac{1}{2}gt^2$

$u_1sin60^{\circ}t-\frac{1}{2}gt^2=u_2t-\frac{1}{2}gt^2$

$u_1sin60^{\circ}t=u_2t$

$\frac{u_1}{u_2}=\frac{1}{sin60^{\circ}}$

$\frac{u_1}{u_2}=\frac{2}{\sqrt{3}}$