Question

Two bodies are thrown from the same point with the same velocity of 50m/s.If their angles of projection are complementary angles and the difference of maximum heights is 30m,their maimum heights

Answer 1

H1+H2 =u^2 sin^2teta ÷2g +u^2sin^(90-teta)

u^2÷2g (sin^2teta +cos^2teta)

u^2÷2g
50^2÷2×10
=125

H1+H2=125
H1-H2=30

H1=77.5m
H2=47.5m

Answer 2

Answer:

Here is your solution.