Physics, asked by deeprajpatidar38, 4 months ago

two bodies are thrown with the same initial velocity at angle a and (90-a) with the horizontal. What will be the ratio of the maximum heights attained by them?

Answers

Answered by sahilzuber3
0

Answer:

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maximum height attained by projectile is ,H=

2g

u

2

sinθ

so, ratio,

H

2

H

1

=

sin(90

0

−α)

sinα

=

cosα

sinα

=tanα

Range is given by, R=

g

u

2

sin2θ

so ratio in both case,

R

2

R

1

=

sin2(90

0

−α)

sin2α

=

sin(180

0

−2α)

sin2α

=

sin2α

sin2α

=1

so, R

1

=R

2

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