Question

Two bodies bearing equal and opposites
charges has a force F between them.
Now they are connected by a conductor
so that 25% of charge from one body
flows to the other. Now the force
between them is:

Answer 1

Explanation:

We know that

F =k q1q2 /r^2

Leads :- Both are opposite and same charge

F₁ = kq² /r²

When 1/4 is given from say +q

Charge on it becomes + 3/4q

Charge on the other body having opposite charge = -1 +1/4 = -3/4q

[take only magnitude]

F₂ = k (+3/4q ) (-3/4q ) /r²

   = 9/16 F₁

                  Hope you understand      

This is Habel Sabu ....... Isn't it the Brainliest