Question

Two bodies each of mass 10 kg attract each other with a force of 0.1 milligram weight. What is the distance between them ?

Answer 1

Answer:

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Answer 2

HEY MATE YOUR ANSWER IS HERE...

$force \: = \frac{gm_{1} m _{2}}{ {d}^{2} }$

LET FORCE = 0.1 milligram

$force \: = 0.1 \times {10}^{ - 6} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 10^{ - 7} kg \\ force \: = 9.8 \times 10^{ - 7} \: newton \:$

${d}^{2} = \frac{gm _{1}m _{2}}{force}$

$g \: = {6.67 \times 10}^{ - 11}$

Hence

${d}^{2} = \frac{{6.67}^{ - 11} \times 10 \times 10}{9.8 \times {10}^{ - 7} }$

$d = \sqrt{68.1 \times {10}^{ - 4} }$

$d = 8.25 \times {10}^{ - 2} meter$

$d \: = 8.25 \: cm$

HOPE IT HELPS THANKS FOR THE QUESTION

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