Question

two bodies have a mass of ratio 4:5 the force applied on the bigger mass produce an a acceleration of 15 m/s². if the same force act on it, calculate the acceleration on the lighter mass?,​

Answer 1

Answer:

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Solution:-

⠀⠀⠀⠀⠀⠀⠀⠀According to the Given Statement

We have to calculate the acceleration produce in 2nd body . As we know that Force is defined as the product of mass & acceleration.

Let the acceleration of 2nd body = A2

It is also given that constant force is applied on both bodies . It means the

• F1 = F2 (both are equal )

where,

• F1 denote Force on 1st body
• F2 denote force on 2nd body

Now,

• Substitute the value we get

:⟹ M1A1 = M2A2 (product of Mass & acceleration)

:⟹ 4×15 = 5× A2

:⟹ 60 = 5 × A2

:⟹ 60/5 = A2

:⟹ A2 = 60/5

:⟹ A2 = 12m/s²

Hence, the acceleration on the lighter mass is 12m/s².

Answer 2

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⠀⠀⠀⠀⠀⠀⠀⠀According to the Given Statement

We have to calculate the acceleration produce in 2nd body . As we know that Force is defined as the product of mass & acceleration.

Let the acceleration of 2nd body = A2

It is also given that constant force is applied on both bodies . It means the

• F1 = F2 (both are equal )

where,

• F1 denote Force on 1st body
• F2 denote force on 2nd body

Now,

• Substitute the value we get

:⟹ M1A1 = M2A2 (product of Mass & acceleration)

:⟹ 4×15 = 5× A2

:⟹ 60 = 5 × A2

:⟹ 60/5 = A2

:⟹ A2 = 60/5

:⟹ A2 = 12m/s²

Hence, the acceleration on the lighter mass is 12m/s².