Two bodies have equal mass. However the speed of the 1st body is thrice the speed of the 2nd body. What is the ratio of kinetic energy of the 1st body with the 2nd body?
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Answer:
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Explanation:
Let , m is mass (both )
1st body velocity v
2nd body velocity 2v
E(1st ) = 1/2mv^2
E(2nd)=1/2m(2v)^2=2mv^2
E(1st)/E(2nd)=(1/2mv^2)/(2mv^2)
E(1st):E(2nd)=1:4
So, ratio is 1:4
Thank you .
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