Question

two bodies having masses 20 kg and 40 kg are separated by 10 mat what distance from body a should another body c of mass 25 kg be placed so that the net gravitational force on se is zero​

Answer 1

Answer:

m1m2/r1^2=m1'm2/r2^2

20*25/(10-x)^2=40*25/x^2

x^2=2(10-x)^2

x=√2(10-x)

x(1+√2)=10√2

x= 10√2/(√2+1)

x=10√2(√2-1)