Question

two bodies having masses 2kg and 20kg moving with a velocity 20m/s and 40m/s from opposite direction then they collide and become a single body. find loss in k.e​

Answer 1

Answer:

Explanation:wo bodies having masses 2kg and 20kg moving with a velocity 20m/s and 40m/s from opposite direction then they collide and become a single body. find loss in k.e​wo bodies having masses 2kg and 20kg moving with a velocity 20m/s and 40m/s from opposite direction then they collide and become a single body. find loss in k.e​wo bodies having masses 2kg and 20kg moving with a velocity 20m/s and 40m/s from opposite direction then they collide and become a single body. find loss in k.e​wo bodies having masses 2kg and 20kg moving with a velocity 20m/s and 40m/s from opposite direction then they collide and become a single body. find loss in k.e​

wo bodies having masses 2kg and 20kg moving with a velocity 20m/s and 40m/s from opposite direction then they collide and become a single body. find loss in k.e​wo bodies having masses 2kg and 20kg moving with a velocity 20m/s and 40m/s from opposite direction then they collide and become a single body. find loss in k.e​wo bodies having masses 2kg and 20kg moving with a velocity 20m/s awo bodies having masses 2kg and 20kg moving with a velocity 20m/s and 40m/s from opposite direction then they collide and become a single body. find loss in k.e​wo bodies having masses 2kg and 20kg moving with a velocity 20m/s and 40m/s from opposite direction then they collide and become a single body. find loss in k.e​wo bodies having masses 2kg and 20kg moving with a velocity 20m/s and 40m/s from opposite direction then they collide and become a single body. find loss in k.e​nd 40m/s from opposite direction then they collide and become a single body. find loss in k.e​

Answer 2

Given :

• m = 2 kg
• m'= 20 kg
• u = 20 m/s
• u' = 40 m/s

To find :

• Loss in KE

Solution :

As no external force is acing on the system the momentum of the system remains conserved .

Initial momentum of the system = Final momentum of the system

⇒ mu + m'u' = (m +m')v

⇒ 2x 20 + 20x - 40 =22 x v  [ u' = - 40 ( moving in opp direction )]

⇒ 40 - 800 = 22 v

⇒ v = - 760/ 22

⇒ v =  - 34.5 m/s

Here the negative sign denotes that after collision the entire system is moving in the direction of the 20 kg mass

⇒ Loss in KE = KE initial - KE final

⇒ Loss in KE =( ½mu² + ½ m'u'² )- ½Mv²

⇒ Loss in KE = (½ x 2 x 400 + ½ x 20 x 40) - ½ x 22 x 1190.5

⇒ Loss in KE =  (400 +400) - 13092.75

⇒ Loss in KE = 800 - 13092.75

⇒ Loss in KE =  - 12,292 J

The loss in KE is 12,292 J .